Total tickets sold = 140
So if the adult ticket is represented by a
and student ticket by s
then we can obtain the system of the equation since the price of the different tickets are known
Total ticket = a + s = 140 ------------------ Equation 1
The cost of adult tickets will be 8 x a = 8a
The cost of student tickets will be 5 x s = 5s
Then total cost = 8a + 5s = 760 ----------------------Equation 2
Solving the two equations simultaneously
Method: Solve Using Elimination Method
Multiply equation 1 by 8 so as to eliminate a
(a + s = 140 x ) =>
8a + 8s = 1120 ------- equation 3
8a + 5s = 760 --------- equation 2
Subtracting equation 2 from equation 3
8s - 5s = 1120 - 760
3s = 360
Divide both sides by 3
s = 360/3
s = 120
That means that 120 children tickets were sold
To get the number of adult tickets sold
We will substitute s = 120 into equation 1
a + s = 140
a + 120 = 140
a = 140 - 120
a = 20