Question

2NO(g) + O2 (g) --> 2NO2

How many moles of O2 are required to produce 46.0 g NO2?

Answer 1

`2NO_((g)) + O_(2)_((g)) -----\ \textgreater \ 2NO _(2)_((g))`

moles of NO₂ =
`(Mass)/(Mr)`

=
`(46.0 g)/(((14 * 1) (16 * 2)))`

= 1 mol

ratio of NO₂ : O₂ = 1 : 2

∴ since mole of NO₂ = 1 mol
the mole of O₂ =
`(1)/(2)` mol
= 0.5 mol