Question

Find the area of a triangle with sides a=5, b=8, and c=11

Answer 1

`Heron's\ formula:\\A_\Delta=s√((s-a)(s-b)(s-c))\ where\ s=(a+b+c)/(2)\\\\a=5;\ b=8;\ c=11\\\\s=(5+8+11)/(2)=(24)/(2)=12\\\\A_\Delta=12√((12-5)(12-8)(12-11))=12√(7\cdot4\cdot1)\\\\=12\sqrt7\cdot\sqrt4=12\sqrt7\cdot2=24\sqrt7`