Question

Passing through (-9,-3) and parallel to the line whose equation is y=2x+1What is the equation for the line in point-slope form?

Answer 1

y + 3 = -2(x + 9)

Explanations:

The equation of a line in point-slope form is expressed as;

`y-y_1=m(x-x_1)`

where

• m is the ,slope

,

• (x1, y1) is any ,point, on the line

Fro the equation of the line given, the required slope is -2 and the point given is (-9, -3)

Substitute the point and slope into the equation above to have

`\begin{gathered} y-(-3)=-2(x-(-9)) \\ y+3=-2(x+9) \end{gathered}`

Hence the equation for the line in point-slope form is y + 3 = -2(x + 9)