Question

the table dispays the scores of students on a recent exam.find the mean of the scores to the nearest 10th

Answer 1

To find the mean, we have to use the following formula

`\bar{x}=(\Sigma(x\cdot f))/(N)`

Where x represents each score and f represents the number of students. Using the given table, we have

`\begin{gathered} \bar{x}=(65\cdot8+70\cdot1+75\cdot2+80\cdot1+85\cdot1+90\cdot9+95\cdot4)/(8+1+2+1+1+9+4) \\ \bar{x}=(520+70+150+80+85+810+380)/(26)=(2095)/(26) \\ \bar{x}\approx80.6 \end{gathered}`

Hence, the mean is 80.6, approximately.