Question

Find the equation of the line with a slope of 3/4 that goes through the point (8,10)

Answer 1

This is good.

Using the general format: y -y1 = m(x-x1), format of a slope and a point.

(x1, y1) = (8,10)

y -10 = (3/4)*(x-8)
y -10 = 3x/4 -6 Multiply through by 4.
4y -40 = 3x -24
4y = 3x -24 + 40
4y = 3x + 16.

So equation of the line is: 4y = 3x + 16.

Answer 2

the answer is ......... y=3/4+10