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What is the approximate value of R in the equation below? (76.4)(.32)(R-112)+(.35)(20R+435)=54
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What is the approximate value of R in the equation below?
(76.4)(.32)(R-112)+(.35)(20R+435)=54

User Gene Goykhman
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1 Answer

4 votes
(76.4)(0.32)(R - 112) + (0.35)(20R + 435) = 54
24.448(R - 112) + 7R + 152.25 = 54
24.448R - 2738.176 + 7R + 152.25 = 54
31.448R - 2585.926 = 54
31.448R = 54 + 2585.926
31.448R = 2639.926
R = 2639.926/31.448
R = 83.9457
User Mja
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