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Find the distance traveled in 35 seconds by an object traveling at a velocity of v(t) = 20 + 5cos(t) feet per second
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Find the distance traveled in 35 seconds by an object traveling at a velocity of v(t) = 20 + 5cos(t) feet per second

User Salazar
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s(t)= \int\limits^(35)_0 {v(t)} \, dt \\ =\int\limits^(35)_0 {(20+5cos(t))} \, dt \\ =[20t+5sin(t)]^(35)_0 \\ =(20(35)+5sin(35))-(20(0)+5sin(0)) \\ =700+2.868=702.868 \, feet
User Ordoshsen
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