Find the distance traveled in 35 seconds by an object traveling at a velocity of v(t) = 20 + 5cos(t) feet per second

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asked Feb 7, 2017 68.0k views

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Find the distance traveled in 35 seconds by an object traveling at a velocity of v(t) = 20 + 5cos(t) feet per second

Mathematics
high-school

Salazar asked

by Salazar

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$s(t)= \int\limits^(35)_0 {v(t)} \, dt \\ =\int\limits^(35)_0 {(20+5cos(t))} \, dt \\ =[20t+5sin(t)]^(35)_0 \\ =(20(35)+5sin(35))-(20(0)+5sin(0)) \\ =700+2.868=702.868 \, feet$

Ordoshsen answered Feb 13, 2017

by Ordoshsen

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