Question

In triangles and and def AB equals 4 AC equals 5 bc equals 7 de equals 10 df equals 13 and fe equals 16 . which method could be used to prove the two triangles similar

Answer 1

We know that

`\begin{gathered} AB=4 \\ AC=5 \\ BC=7 \\ DE=10 \\ DF=13 \\ FE=16 \end{gathered}`

Let's make a diagram

First, we have to find the common ratio dividing corresponding sides

`\begin{gathered} (DE)/(AB)=(10)/(4)=2.5 \\ (DF)/(AC)=(13)/(5)=2.6 \\ (EF)/(BC)=(16)/(7)=2.3 \end{gathered}`

As you can observe, neither ratio is equal. If there's no common ratio, then, the triangles are no similar.

Hence, the answer is none.