Question

A boy throws a stone straight upward with an initial

speed of 17.0 m/s.
Part A
What maximum height will the stone reach before falling back down?

Answer 1

14.8m

Step-by-step explanation:

Given parameters:

Initial speed = 17m/s

Unknown:

Maximum height = ?

Solution:

At the maximum height, the final speed will be 0m/s;

We use of the kinematics equation to solve this problem.

V² = U² - 2gH

V is the final velocity

U is the initial velocity

g is the acceleration due to gravity

H is the height

0² = 17² - (2 x 9.8 x h )

0 = 289 - (9.6h)

-289 = -19.6h

h = 14.8m