Answer:
What is the net force on the block shown above?
★F(app) =25N, F(G) =60N
★F(app) =95N, F(G)=60N✓
★F(app) =60N, F(G) =25N
★F(app) =60N, F(G) =95N
Step-by-step explanation:
Net Force 60N Right
→F(app) = 60+F(frict) = (60+35) = 95 N
→F(N)= F(G) = 60 N