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If 2x = 5, 3y = 4, and 4z = 3, what is the value of 24xyz ?

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We have : 2x = 5 ⇔ x = 5/2
3y = 4 ⇔ y = 4/3
4z = 3 ⇔ z = 3/4
⇒ 24xyz = 24 × 5/2 × 4/3 ×3/4 = 60
User Arthur Putnam
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