Question

An object initially at rest experiences an acceleration

of 1.4 m/s for 5.0 s and then travels at that
constant velocity for another 6.0 s.
Part A
What is the object's average velocity over the 11 s interval?

Answer 1

1.4m/s

Step-by-step explanation:

Average velocity is the total distance covered divided by the total time taken.

Average velocity =
`(total distance )/(time )`

Total time taken = 5s + 6s = 11s

The first distance covered = velocity x time = 1.4 x 5 = 7m

second distance covered = velocity x time = 1.4 x 6 = 8.4m

So;

Average velocity =
`(7 + 8.4)/(11)` = 1.4m/s