Question

For y = 4x + 2x2 – x3, show how to find the value for y, when x = 2. Show your work

Answer 1

`Start \ with \ the \ original \ equation`


`y=4x+2x^2-x*3`


`Let \ x=2`


`y=4*2+2*2^2-2*3`


`\fbox{y = 10}`

Answer 2

If you would like to find the value of y for x = 2, you can do this using the following steps:

y = 4 * x + 2 * x^2 – x^3
x = 2
y = 4 * 2 + 2 * 2^2 - 2^3 = 8 + 2 * 4 - 8 = 8 + 8 - 8 = 8

The correct result would be y = 8.