181k views
15 votes
Seven year back the age of a father was 5 times the age of

his son. It will be twice after 14 years. Find their ages at
present.

User Chui
by
6.2k points

1 Answer

9 votes

Explanation:

x = age of father

y = age of son

x - 7 = 5(y - 7) = 5y - 35

x = 5y - 28

x + 14 = 2(y + 14) = 2y + 28

we use the identity of the first equation in the second equation :

5y - 28 + 14 = 2y + 28

3y = 28 + 28 - 14 = 42

y = 14

x = 5y - 28 = 5Ă—14 - 28 = 70 - 28 = 42

the father is currently 42 years old.

the son is currently 14 years old.

User Fredrik Johansson
by
6.7k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.