Question

PLEASE HELP Solve the following problems: Find the indicated values, mAB, m ABC, mBAC, mACB

Answer 1

see explanation

Explanation:

The angle at the centre of a circle is equal to the measure of the arc that subtends it, thus

AB = ∠ AOB = 49°

The measure of arc BC = 360° - (49 + 107)° = 360° - 156° = 204°, then

ABC = AB + BC = 49° + 204° = 253°

BAC = BA + AC = 49° + 107° = 156°

ACB = AC + CB = 107° + 204° = 311°

Answer 2

it already shows that AB is 49°

in order to find ABC you must first find BC

360 - (AC + AB) = BC
360 - 156 = BC
204° = BC

NOW add BC with AB

49 + 204
253

angle ABC is 253°

now to find BAC add AB and AC
49 + 107 = 156°

angle BAC is 156°

FINALLY to find ACB add AC and CB

107 + 204
311°

angle ACB is 311°