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The equation of line k is y=-1/5x -1/8. What is the equation of the line that is perpendicular to line k and passes through (0,0)?

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y=-1/5 x-1/8
Gradient, m= -1/5
A line perpendicular will be;
m=15
y=mx+c
Replacing for x and y;
0=5(0)+c
c=0
y=5x
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