Answer:
Minimum number of gallons pumped after 30 days = 24,192,000 gallons
Explanations:
The minimum amount of water pumped in 1 minute = 1120 gallons
The minimum number of hours used for pumping per day = 12 hours
Number of minutes in 1 hour = 60 minutes
Number of minutes in 12 hours = 12 x 60 = 720 minutes
The minimum amount of water pumped per day = 1120 x 720
The minimum amount of water pumped per day = 806400 gallons
Let the number of days used for pumping be x
Let the total number of gallons pumped x days after pumping begins = y
Since 806400 gallons is pumped per day:
y = 806400x
Minimum number of gallons pumped after 30 days, that is, x = 30
y = 806400 (30)
y = 24,192,000 gallons
Minimum number of gallons pumped after 30 days = 24,192,000 gallons