Question

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A scuba diver dove from the surface of the ocean to an elevation of −49 9/10
feet at a rate of −15.4 feet per minute. After spending 13.75 minutes at that elevation, the diver ascended to an elevation of −8 9/10
feet. The total time for the dive so far was 20 1/8
minutes. What was the rate of change in the diver's elevation during the ascent? Round your answer to the nearest hundredth.


The rate of change of the diver's elevation was _____ft/min.

Answer 1

S=v*t=-49.9*13.75=-686.125 feet
ΔS=-686.125-(-8.9)=-677.225 feet
20 1/8-13 3/4= 6 3/8= 6.375 minutes
v=S/t=-677.25/6.375=-106.24 feet per minute
the rate was -106.24 feet per minute of change in the diver's elevation during the ascent