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A 15kg. Blob of "space clay" moving at a speed of 3m/s slams I to a 12.5 blob of "space clay" at rest. They stick together after colliding, but what is their new speed? What's the formula used and how
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Jul 5, 2015
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A 15kg. Blob of "space clay" moving at a speed of 3m/s slams I to a 12.5 blob of "space clay" at rest. They stick together after colliding, but what is their new speed?
What's the formula used and how do you solve this...?
Physics
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Stimy
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Use the principle of conservation of momentum ... momentum after the collision is equal to the momentum before it.
Momentum = (mass) x (speed)
.
Momentum before the collision:
Big blob . . . (15) x (3) = 45 kg-m/s
Little blob . . (12.5) x (0) = zero.
Total . . . . . . 45 kg-m/s
Momentum after they meet and stick:
Combined blob . . . (15+12.5) x (speed)
Momentum after = momentum before:
(27.5) x speed = 45 kg-m/s
Divide each side by 27.5 :
Speed = 45 / 27.5 =
1.636 m/s
(rounded)
Kisinga
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Jul 10, 2015
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