Question

I need help I'm terrible at math

Answer 1

`Use:\\\left((a)/(b)\right)^n=(a^n)/(b^n)\\\\(a^n)^m=a^(n\cdot m)\\\\(a\cdot b)^n=a^nb^n\\\\a^(-n)=(1)/(a^n)`



`\left((x^3)/(2y^6)\right)^(-3)=((x^3)^(-3))/((2y^6)^(-3))=(x^(3\cdot(-3)))/(2^(-3)(y^6)^(-3))=(x^(-9))/((1)/(2^3)y^(6\cdot(-3)))`


`=(x^(-9))/((1)/(8)y^(-18))=((1)/(x^9))/((1)/(8y^(18)))=(1)/(x^9):(1)/(8y^(18))=(1)/(x^9)\cdot(8y^(18))/(1)=\boxed{(8y^(18))/(x^9)}`