Question

Jillian’s school is selling tickets for a play. The tickets cost $10.50 for adults and $3.75 for students. The ticket sales for opening night totaled $2071.50. The equation 10.50a + 3.75b = 2071.50, where a is the number of adult tickets sold and b is the number of student tickets sold, can be used to find the number of adult and student tickets. If 82 students attended, how may adult tickets were sold?

Answer 1

The correct answer would be , a = 168 tickets were sold

Explanation:

Cost of adults ticket = $10.5

Cost of Students Ticket = %3.75

Sales Totals for opening night = $2071.5

Equation would be

10.5a + 3.75b = 2071.5

If 82 students attended the the play at that night, it means the value of b would be 82. Thus substituting the value in the above equation, we can find the value of a, which means how many adult tickets were sold.

10.5a + 3.75(82) = 2071.5

10.5a + 307.5 = 2071.5

10.5a = 2071.5-307.5

10.5a = 1764

a= 168 tickets were sold.

Answer 2

Given:
b = 82
\
Asked:
a = number of adult tickets sold = ?

Solution:
10.50(a) + 3.47(82) = 2071.50

solving for a:

a= [2071.5-3.47(82)]/10.50

a=168

FINAL ANSWER: There were 168 adult tickets sold.