Question

Log(x) + log (4) = log(12)

Answer 1

The equation is given below as

`logx+log4=log12`

By applying the logarithm law of multiplication, we will have

`logM+logN=logMN`

By substituting the values, we will have

`\begin{gathered} logx+log4=log12 \\ log(4* x)=log12 \\ 4x=12 \\ (4x)/(4)=(12)/(4) \\ x=3 \end{gathered}`

Hence,

The value of x is

`\Rightarrow x=3`