Question

What is the general form of the equation of a circle with its center at (-2, 1) and passing through (-4, 1)?

Answer 1

The equation of circle is:
(x-a)^2+(y-b)^2=r^2 where C(a, b) is the center.
In order to find r you have to find the distance between C(-2, 1) and let's say A(-4, 1)

The formula for distance is:

`\sqrt{ ( y_(A)-y_{C )^(2) + (x_(A)- x_(C )^(2) )`
r = 2

The equation of circle is
(x+2)^2+(y-1)^2=4

I hope that this is the answer that you were looking for and it has helped you.