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Iron has a density of 7.9 g/cm3. What is the mass of a cube of iron with the length of one side equal to 55.0 mm?

1 Answer

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Answer:

Mass, m = 1.31 kg

Step-by-step explanation:

It is given that,

Density of iron,
d=7.9\ g/cm^3

Side of cube, a = 55 mm = 5.5 cm

We need to find the mass of the cube of iron. Mass per unit volume is called the density of the substance. It is given by :


d=(m)/(V)


d=(m)/(a^3)


m=d* a^3


m=7.9* (5.5)^3

m = 1314.36 grams

or

m = 1.31 kg

So, the mass of the iron cube is 1.31 kg. Hence, this is the required solution.

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