Question

a mixture of oxygen, hydrogen, and nitrogen gases exerts a total pressure of 282 kpa. if the partial pressures of oxygen and hydrogen are 110 kpa and 106 kpa respectively, what is the partial pressure exerted by nitrogen?

Answer 1

pressures oxygen and hydrogen + pressure nitrogen

110 Kpa + 106 Kpa = 216 Kpa

Partial pressure:

total pressure - exerted by nitrogen:

282 Kpa - 216 Kpa

= 66 Kpa

hope this helps!

Answer 2

Answer : The partial pressure of
`N_2` is, 66 Kpa

Solution :

According to the Dalton's law, the total pressure of the gas is equal to the sum of the partial pressure of the mixture of gasses.

`P_T=p_(N_2)+p_(O_2)+p_(H_2)`

where,

`P_T` = total partial pressure = 282 Kpa

`P_(N_2)` = partial pressure of nitrogen = ?

`P_(O_2)` = partial pressure of oxygen = 110 Kpa

`P_(H_2)` = partial pressure of hydrogen = 106 Kpa

Now put all the given values is expression, we get the partial pressure of the nitrogen gas.

`282Kpa=p_(N_2)+110Kpa+106Kpa`

`p_(N_2)=66Kpa`

Therefore, the partial pressure of
`N_2` is, 66 Kpa