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3[2(x-3)+2]+5(x-3)
algebra2

2 Answers

3 votes
11x-27 is the answer
User Micke
by
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5 votes
Perform what's inside the brackets first
"2(x-3)+2" ---> 2x-6+2 ---> simplify (add the 2 and the -6 together) ---> 2x-4 ---> put your simplified version back into the brackets ---> [2x-4]

Now multiply your 3 with whatever is in the brackets to get rid of the brackets
"3[2x-4]"
6x-12

Do the same with the 5 and whatever is still in parenthesis after the 5
"5(x-3)"
5x-15

Add the two simplified terms together
"6x-12+5x-15"
combine the like terms ---> 6x+5x=11x and -12(+)-15=-27

Put your two answers back into one equation
"11x-27"

And that is your final answer
User Hereiam
by
7.7k points

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