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What is the ph of a solution with [oh-] = 2.6 × 10^-3 m?
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What is the ph of a solution with [oh-] = 2.6 × 10^-3 m?

User Prathik Rajendran M
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1 Answer

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pOH = - log [ OH⁻]

pOH = - log [ 2.6x10⁻³]

pOH = 2.58

pH + pOH = 14

pH + 2.58 = 14

pH = 14 - 2.58

pH = 11.42

User Sam Routledge
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