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Calculate the [oh−] in a solution with a ph of 12.52.

User Aref
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2 Answers

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Final answer:

To calculate the [OH-] in a solution with a pH of 12.52, use the formula pH + pOH = 14.00. Subtract the pH from 14 to get pOH, then calculate [OH-] using the concentration of hydroxide ions formula.

Step-by-step explanation:

To calculate the [OH-] in a solution with a pH of 12.52, we can use the formula pH + pOH = 14.00. Since the pH is 12.52, we can calculate the pOH by subtracting the pH from 14.00:

pOH = 14.00 - 12.52 = 1.48

The pOH represents the concentration of hydroxide ions, [OH-]. So in this solution, the concentration of [OH-] is 10-pOH:

[OH-] = 10-1.48 = 0.029 M

User CmdrMoozy
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pH + pOH = 14

12.52 + pOH = 14

pOH = 14 - 12.52

pOH = 1.48

[OH⁻] = 10^ -pOH

[OH⁻] = 10 ^- 1.48

[OH⁻] = 0.033 M
User Exitos
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