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A 35 N force makes a 10 degree angle with the positive x-axis. What is the magnitude of the vertical component of the force?

User Lkanab
by
8.6k points

2 Answers

5 votes

Answer:

Vertical component of force is equal to
6.067 N

Step-by-step explanation:

The magnitude of the vertical component on any force when α is the angle between the direction of force and the X -axis is


F_y = F * Sin\alpha

Substituting the given values in above equation, we get -


F_y = 35 * Sin 10\\F_Y = 35 * 0.1736\\F_Y = 6.067

Vertical component of force is equal to
6.067 N

User Johnspackman
by
8.8k points
6 votes

Answer:

6.07 N

Step-by-step explanation:

Given that,

Force, F = 35 N

It makes 10 degree angle with the positive x-axis.

We need to find the magnitude of the vertical component of the force. It can be given by :


F_y=F\sin\theta\\\\=35* \sin(10)\\\\=6.07\ N

So, the magnitude of the vertical component of the force is 6.07 N.

User Awithrow
by
9.0k points

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