Write the log equation as an exponential equation. You do not need to solve for x. log(x-1) (x^2 + 5x

Thomasb asked May 1, 2023

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Write the log equation as an exponential equation. You do not need to solve for x. log(x-1) (x^2 + 5x – 17) = x - 1

Thomasb asked May 1, 2023

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19 votes

$\begin{gathered} \log _((x-1))(x^2+5x-17)=x-1 \\ x^2+5x-17=(x-1)^(x-1) \\ \end{gathered}$

Note you just need to cross the base to the right side to the exponential of x-1.

StarPilot answered May 6, 2023

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