Question

A system of two equations is shown below:Equation C: a = 4b + 5Equation D: a = 6b − 2What value of a can be substituted into equation D to solve the system of equations? (5 points)4b + 56b − 24b6b

Answer 1

Given;

`\begin{gathered} EquationC:a=4b+5 \\ \\ EquationD:a=6b-2 \end{gathered}`

Substitute the value of a in equation D to solve the system of equation;

`\begin{gathered} 4b+5=6b-2 \\ \\ 2b=3 \\ \\ b=(3)/(2) \\ \\ a=4((3)/(2))+5 \\ \\ a=11 \end{gathered}`

CORRECT ANSWER: 4b+5