Question

What would the charge need to be on an object so that a 5.2 x 10^-6 Ccharge that is separated by a distance of.28 m would experience anattractive force of 220 N?(Don't forget your units!)Your answer

Answer 1

Answer:
`q_2\text{ = }3.69\text{ }*10^(-4)C`Explanations:

According to Coulomb's law, the force of attraction between two different charges q₁ and q₂ and separated by a distance r is given by the formula:

`F\text{ = }(kq_1q_2)/(r^2)`
`q_1\text{ = 5.2 }*10^(-6)C`

The force, F = 220N

The distance separating the two charges, r = 0.28

`F\text{ = }(kq_1q_2)/(r^2)`

To find the charge second q₂, substitute q₁, k, F, and r into the formula above

`\begin{gathered} 220\text{ = }(9*10^9*5.2*10^(-6)* q_2)/(0.28^2) \\ 220\text{ = }(46800* q_2)/(0.0784) \\ 220*0.0784\text{ = 46800 }* q_2 \\ q_2\text{ = }(220*0.0784)/(46800) \\ q_2\text{ = }3.69\text{ }*10^(-4)C \end{gathered}`