Factor completely 2x^3 + 22x^2 + 36x

asked Feb 17, 2015 157k views

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Factor completely

2x^3 + 22x^2 + 36x

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3 votes

$2x^3 + 22x^2 + 36x=\\ 2x(x^2+11x+18)=\\ 2x(x^2+9x+2x+18)=\\ 2x(x(x+9)+2(x+9))=\\ 2x(x+2)(x+9)$

Ketan Akbari answered Feb 19, 2015

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6 votes

$2x^3+22x^2+36x \to\boxed{2x(x^2+11x+18)} \\\\ 2x(x^2+9x+2x+18)= \\\\ =2x[x(x+9)+2(x+9)]= \\\\ = \boxed{\boxed{2x(x+9)(x+2)}}$

Ves answered Feb 21, 2015

by Ves

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