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Find the first derivative of y = sin^2(cos2x)
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Find the first derivative of y = sin^2(cos2x)

User Nirav D
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1 Answer

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Hello,

y=sin²(cos(2x))
y'=2*sin(cos(2x))*cos(cos(2x))*(-sin(2x)*2)
= -4*sin(cos(2x))*cos(cos(2x))*sin(2x)
User Narmageddon
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