Question

A solution has a [oh−] of 1 x 10−12. what is the poh of this solution? 2 7 10 12

Answer 1

pOH = - log [ OH-]

pOH = - log [ 1 x 10⁻¹²]

pOH = 12

Answer 2

12

Step-by-step explanation:

p(oh) = - log ( concentration of the oh) = -log (1* 10^-12) = - (-12) = 12