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What's the missing variable for 1/3n+3=-n-2
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What's the missing variable for 1/3n+3=-n-2

User Cosinepenguin
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1 Answer

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(1)/(3)n + 3 = -n - 2 Multiply both sides by 3 to cancel out the fraction
n + 9 = -3n - 6 Add 3n to both sides
4n + 9 = 6 Subtract 9 from both sides
4n = -3 Divide both sides by 4
n =
- (3)/(4)
User Ryan Jenkin
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