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What is the volume of 3.50 moles of oxygen gas (O2) at 273 K and 1.00 atm?

1 Answer

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p x V = n x R x T

1.00 x V = 3.50 x 0.082 x 273

1.00 x V = 78.351

V = 78.351 / 1.00

V = 78.351 L
User Antonio Moore
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