Answer:
Explanation:
The angle measure we need is twice the angle ACB.
Find its measure considering AB = 4/2 = 2 in and BC = 6 in.
Use trigonometry:
- tan(∠ACB) = AB/BC = 2/6 = 1/3
- m∠ACB = artctan (1/3)
- m∠ACB = 18.43° (rounded)
The angle between the line segments is: