Question

need help on my physics test review.a train moves from rest to a speed of 25 m/s in 30.0 secs. whats the acceleraton?

Answer 1

Use the following kinematic equation:

`a=(v-v_o)/(t)`

where,

v: final speed = 25m/s

vo: initial speed = 0m/s

t: time interval = 30.0s

a: acceleration = ?

replace the previous values of the parameters into the expression for a and simplify:

`a=(25(m)/(s)-0(m)/(s))/(30.0s)\approx0.83(m)/(s^2)`

The acceleration of th train is approximately 0.83m/s^2