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Find the integral of arccos x /sqrt (1-x^2)dx.

User Azra
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The problem ask to find the integral of the trigonometric equation of arcos x/qrt(1-x^2)dx and the best answer that i could give base on the given equation and my further computation and that is ∫arccos(x)/sqrt(1−x2dx)=1/2(arccos(x))2+c. I hope are satisfied with my answer and feel free to ask for more
User Sudhakar Krishnan
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