Question

What is the remainder when (2x3 4x2 − 32x 18) ÷ (x − 3)?

Answer 1

Hello,

f(x)=2x^3+4x²-32x+18
f(3)=2*3^3+4*3²-32*3+18=12

Remainder =12

Answer 2

Answer: The remainder will be 12.

Explanation:

Since we have given that

`f(x)=(2x^3+4x^2 -32x+18)`

And
`g(x)=x-3`

Now, we need to find the remainder while dividing f(x) by g(x).

So, by using "Remainder theorem" we get our answer.

`g(x)=0\\\\x-3=0\\\\x=3`

Now, we use x=3 in f(x).

`f(3)=2x^3+4x^2-32x+18\\\\f(3)=2(3)^3+4(3)^2-32(3)+18\\\\f(3)=2* 27+4* 9-96+18\\\\f(3)=54+36-96+18\\\\f(3)=12`

so, the remainder will be 12.