Question

When Mrs. Myles gave a test, the scores were normally distributed with a mean of 72 and a standard deviation of 8. This means that 95% of her students scored between which two scores?

Answer 1

Given a standardized test with a mean score of 78 and a standard deviation of 5.9, a student who scored in the 60th percentile could have a score of:
a. 84
b. 72
c. 79
d. 76
the answer is c

Answer 2

The score of Mr.Myles is between 56 and 88.

Explanation:

Given : When Mrs. Myles gave a test, the scores were normally distributed with a mean of 72 and a standard deviation of 8.

To find : The class interval at 95% of her students scored between which two scores?

Solution :

We have given,

Mean
`\mu=72`

Standard deviation
`\sigma=8`

The class interval at 95% is given by

`\mu-2\sigma\leq CI\leq \mu+2\sigma`

Substitute the values in the formula,

`72-2(8)\leq CI\leq 72+2(8)`

`72-16\leq CI\leq 72+16`

`56\leq CI\leq 88`

Therefore, The score of Mr.Myles is between 56 and 88.