Solve the compound inequality 10 >= 7 + 3x and 9-4x<=1 . show steps please.

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asked Jul 8, 2017 86.7k views

2 Answers

Numediaweb · Answer 1 · 2017-07-11T03:13:04+0000

3x + 7 ≤ 10 and -4x + 9 ≤ 1
- 7 - 7 - 9 - 9 Subtract the numbers from each side.
3x ≤ 3 -4x ≤ -8 Divide it by the same number.
3 3 -4 -4
x ≤ 1 x ≥ 2 Find the solution.

Solution Set: x, [2, 1]

Hodson · Answer 2 · 2017-07-13T16:04:24+0000

10 >= 7 + 3x -4x+9<=1
-7 >= -7 - subtract 7 -9<=-9 - Subtract 9
__________ ___________
3 >=3x - divide by 3 -4x<=-8 - divide by -4

x>=1 x<=2

Solve the compound inequality 10 >= 7 + 3x and 9-4x<=1 . show steps please.

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