Question

Can someone help me solve this problem asap

Answer 1

Hello,

We suppose x≠-2.


`(x^2+5x-2)/(x+2)=3\\\\ ==\textgreater \ (x^2+5x-2-3(x+2))/(x+2)=0\\\\ ==\textgreater \ x^2+4x-2x-8=0\\ ==\textgreater \ x^2+4x-2x-8=0\\ ==\textgreater \ x(x+4)-2(x+4)=0\\ ==\textgreater \ (x+4)(x-2)=0\\ ==\textgreater \ x=-4 \ or \ x=2\\\\ Proof:\\ if\ x=-4\ then \ \ ((-4)^2+5*(-4)-2)/(-4+2) =(16-20-2)/(-2)=(-6)/(-2)=3\\\\ if\ x=2\ then \ \ ((2)^2+5*(2)-2 )/(2+2) =(4+10-2)/(4)=(12)/(4)=3\\\\`

Answer 2

view attachment :) hope i helped