Question

In the reaction Mg (s) + 2HCl (aq) H2 (g) + MgCl2 (aq), how many moles of hydrogen gas will be produced from 75.0 milliliters of a 1.0 M HCl in an excess of Mg?

Answer 1

HCl is limiting reactant, Mg in excess therefore:

number of moles HCl:

75.0 mL in liters: 75.0 / 1000 => 0.075 L

Molarity HCl = 1.0 M

n = M x V

n = 1.0 x 0.075

n = 0.075 moles of HCl

Mg(s) + 2 HCl (aq) = H2 (g) + MgCl2 (aq)

2 moles HCl -------------------- 1 mole H2
0.075 moles of HCl ------------ ( moles H2)

moles H2 = 0.075 x 1 / 2

moles H2 = 0.075 / 2

= 0.0375 moles of H2

hope this helps!

Answer 2

Number of moles Hydrochloric Acid (HCL) = 0.0750*1.0
= 0.0750
Hydrochloric Acid and Hydrogen have a ratio of 2 is to 1

Number of moles Hydrogen = 0.0750/2
= 0.0375