M₁V₁ = M₂V₂ (where M₁ & V₁ are the starting molarity and volume and
M₂ & V₂ are the molarity and volume after dilution)
Substitute known values into the equation and use letters to represent unknown
(0.5M) (250ml) = (x) (840ml)
since 1 ml = 1cm³ then
(0.5M) (250cm³) = (x) (840cm³)
transpose and solve for x


∴ molarity when diluted to 840 ml = 0.149 M