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If 250ml of 0.5m nacl solution is diluted to 840ml what is the molarity of the resulting solution

User Wing Lian
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M₁V₁ = M₂V₂ (where M₁ & V₁ are the starting molarity and volume and M₂ & V₂ are the molarity and volume after dilution)

Substitute known values into the equation and use letters to represent unknown
(0.5M) (250ml) = (x) (840ml)

since 1 ml = 1cm³ then
(0.5M) (250cm³) = (x) (840cm³)

transpose and solve for x


x = ((0.5M)(250cm^(3)) )/((840cm^(3)))


x = ((125 M)cm^(3) )/((840cm^(3)))

∴ molarity when diluted to 840 ml = 0.149 M

User Parisa
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