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You accidently throw your car keys horizontally at 8.0 m/s form a cliff 64m high. How far from the base of the cliff should you look for the keys?

User Eddy Borja
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The formula that applies to the problem is this equation on projectile motion expressed as:
y = x tan θ − ½ g x2 / (v0 cos θ)^2.
We are given with y equal to 64 m , θ is zero degrees and vO equal to 8.0 m/s. By substitution, the x then is equal to 28.91 meters.
User Despicable
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