Question

Determine the general form of the equation of a circle with a center at the origin and a radius of 11.

Answer 1

The general equation of a circle is expressed as:

(x-a)^2+ (y-b)^2 = r^2

Where the point (a, b) is the center of the circle and r is the radius.
For the given circle, center is (0,0) and r=11

Therefore, the equation of the circle would be:
(x)^2+ (y)^2 = 11^2
(x)^2+ (y)^2 = 121

Answer 2

The general equation of a circle is given by;

`(x-a)^(2)+ (y-b)^(2) = r^(2)`
Where (a, b) is the centre of the circle and r is the radius.
For the given circle, centre is (0,0) and r=11

`(x-0)^(2) + (y-0)^(2) = 11^(2)`

`x^(2) + y^(2) = 11^(2)`